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Extra info for An Elementary Treatise on the Differential Calculus Founded on the Method of Rates or Fluxions
This version of the MESI protocol does not supply data in the E state. Some versions do. 6 a. 4 Chapter 4 Solutions ■ L-33 b. p0: read 120 Read miss, satisfied in memory, sharers both to S p0: write 120 <-- 60 Both send invalidates Both: 100 + 15 = 115 stall cycles c. p0: read 100 Read miss, satisfied in memory, no sharers MSI: S, MESI: E p0: read 120 Read miss, memory, silently replace 120 from S or E Both: 100 + 100 = 200 stall cycles, silent replacement from E d. p0: read 100 Read miss, satisfied in memory, no sharers MSI: S, MESI: E p1: write 100 <-- 60 Write miss, satisfied in memory regardless of protocol Both: 100 + 100 = 200 stall cycles, don’t supply data in E state (some protocols do) e.
49% of the volume (again, 20 bytes extra per data 20 block, or ------------ . 4096 b. The answer here requires us to add a single parity block per file. 5 GB volume? One way to figure this out is to assume you have 1000 files distributed by size as per the distribution above. Then you would have 266 1-KB files, 110 2-KB files, and so forth. 9668 MB. 9668 MB -------------------- = -----------------------------n files 1000 files Solving for n, we get roughly 242,975 files. 01% of the volume).
Thus the 2-way takes 54% more time than the direct-mapped, while the 4-way takes 53% more time than the directmapped cache. 5 Chapter 5 Solutions ■ L-47 b. 8% greater for the 64 KB. c. 06 ns. The larger cache is 8 times larger but has a 43% larger access time. This growth is between square root and logarithmic, but closer to log. d. 88 ns. 90 ns. 2 a. 11 cycles. 26. b. 56 ns. 63, or 63% faster execution. c. 93! d. 79, or 21% less power. 3 a. 58 pipe stages. b. 14. 34. c. There are two banks. Assuming a random distribution of addresses and a steady stream of accesses, each access has a 50% probability of conflicting with the previous access.